If it's not what You are looking for type in the equation solver your own equation and let us solve it.
113=x^2
We move all terms to the left:
113-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+113=0
a = -1; b = 0; c = +113;
Δ = b2-4ac
Δ = 02-4·(-1)·113
Δ = 452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{452}=\sqrt{4*113}=\sqrt{4}*\sqrt{113}=2\sqrt{113}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{113}}{2*-1}=\frac{0-2\sqrt{113}}{-2} =-\frac{2\sqrt{113}}{-2} =-\frac{\sqrt{113}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{113}}{2*-1}=\frac{0+2\sqrt{113}}{-2} =\frac{2\sqrt{113}}{-2} =\frac{\sqrt{113}}{-1} $
| x=13(12/24) | | 18=-x-5x | | 2*3^(2x+2)=18 | | 4s-23=25 | | 1.75+2x=6 | | 105−n−1=29 | | 3x-7+5x=4(2x+6) | | 5(b-4)=7(2b+1) | | 1/8(2x-7)=1/4(x-1/4) | | $$105−n−1=29 | | 2x^=x^+x | | -2x²-9x-4=0 | | -20=6-2x | | 175m-100m+42975=45450-150m | | 3x²-24x+36=0 | | -4/3(12m+27)=-57-9m | | 2*3^2x+2=18 | | 1+6-x=-9 | | -x-10=-4x | | 4.16+0.75x=5.66+0.66x | | 3x^2+231=-54x | | 10x−8—3−4x=6x | | 4.16+0.75x=5.66+0.66 | | 5+k/3=11 | | 3(x+3)-7=(5(x-4)+18 | | a5+5=10 | | 27–(-16)=x | | 10x–6=104 | | 0.5(9x+18)=−1.5(5x)−2(3x+4.5) | | 8)-8=-16+x | | t+73=4 | | 3(x3)-7=(5(x-4)+18 |